There are three integers A, B, and C.
The product of A and B is 408, the product of A and C is 336, and the sum of B and C is 62.
Find the integer B.
The product of A and B is 408, the product of A and C is 336, and the sum of B and C is 62.
Find the integer B.
Answer
Therefore, A = 744/62 = 12.
B = 408/12 = 34 .
34
Solution
This problem is denoted by a formula, it is
A × B = 408, A × C = 336, and B + C = 62.
A × B + A × C = 408 + 336 = 744
According to the distributive principle, this formula is to be A × (B+C) = 744.
Since it is B + C = 62, it is A × 62 = 744.
A × B + A × C = 408 + 336 = 744
According to the distributive principle, this formula is to be A × (B+C) = 744.
Since it is B + C = 62, it is A × 62 = 744.
Therefore, A = 744/62 = 12.
B = 408/12 = 34 .
