A certain product are sold at A store, B store, and C store.
Total of 6867 pieces sold in three stores this month and the number of product increased more than the previous month was same in each store.
It means that in this month total sales of this product was increased by 15% in A store, 10% in B store and 6% in C store.
Find the sum total number of the sales of three stores in the previous month.
Total of 6867 pieces sold in three stores this month and the number of product increased more than the previous month was same in each store.
It means that in this month total sales of this product was increased by 15% in A store, 10% in B store and 6% in C store.
Find the sum total number of the sales of three stores in the previous month.
Answer
It is reset to A = 20, B = 30, and C = 50 in order to make it easy to calculate.
As for sales this month, 20 × 1.15 = 23, 30 × 1.1 = 33, and 50 × 1.06 = 53.
23 + 33 + 53 = 109 is equivalent to 6867 pieces.
Since the sum total of sales of the previous month is set to 20 + 30 + 50 =100, it is 6867 × 100/109 = 6300 pieces.
6300 pieces
Solution
If the sales number of the previous month is set to A, B, and C, respectively, A × 15% = B × 10% = C × 6%.
Thus, A : B : C = 1/15 : 1/10 : 1/6 = 2 : 3 : 5.
Thus, A : B : C = 1/15 : 1/10 : 1/6 = 2 : 3 : 5.
It is reset to A = 20, B = 30, and C = 50 in order to make it easy to calculate.
As for sales this month, 20 × 1.15 = 23, 30 × 1.1 = 33, and 50 × 1.06 = 53.
23 + 33 + 53 = 109 is equivalent to 6867 pieces.
Since the sum total of sales of the previous month is set to 20 + 30 + 50 =100, it is 6867 × 100/109 = 6300 pieces.
