A is a number with same number of each place in a four-digit integer.
B is a four-digit integer which consists of two kinds of numbers.
In case of A × B = 44448888, find the number of B.
B is a four-digit integer which consists of two kinds of numbers.
In case of A × B = 44448888, find the number of B.
Answer
Based on that A × B = a × 1111 × B = 44448888, a × B = 44448888 / 1111 = 40008.
Furthermore, it is 40008 = 2 × 20004 = 4 × 10002 = 6 × 6668 = 8 × 5001.
The number consisting of a number of two types is 6668.
6668
Solution
According to that A is a number with same number of each place in a four-digit integer, I can find that A is a multiple of 1111 or A = a × 1111.
Based on that A × B = a × 1111 × B = 44448888, a × B = 44448888 / 1111 = 40008.
Furthermore, it is 40008 = 2 × 20004 = 4 × 10002 = 6 × 6668 = 8 × 5001.
The number consisting of a number of two types is 6668.
