May 11 of a certain year was Tuesday.
What day of the week is October 7 of this certain year?
What day of the week is October 7 of this certain year?
Answer
In May there are 21 days including May 11 and number of days from September 1 to October 7 is 30(June) + 31(July) + 31(August) + 30(September) + 7(October) = 129.
In total there 150 days from May 11 to October 7. 150/7=21 remainder 3.
There is 21 times ( one cycle ) for one week starting from Tuesday(May 11), the remainder is called 3.
Since Thursday is the third day of the week starting from Tuesday falls on 150 days, October 7 is Thursday.
Thursday
Solution
The number of days from May 11 to October 7 is to be counted. In May there are 21 days including May 11 and number of days from September 1 to October 7 is 30(June) + 31(July) + 31(August) + 30(September) + 7(October) = 129.
In total there 150 days from May 11 to October 7. 150/7=21 remainder 3.
There is 21 times ( one cycle ) for one week starting from Tuesday(May 11), the remainder is called 3.
Since Thursday is the third day of the week starting from Tuesday falls on 150 days, October 7 is Thursday.
