There is a triangle ABC.
On the side AB, there is a point D so as to AD : DB = 2 : 1.
On the side BC, there is a point E so as to BE : EC = 3 : 1.
Moreover, the intersection of AE and CD is set to P and the intersection of extension of BP and AC is set to F.
(1) Find the area of the triangle ACP.
(2) Find the ratio of the length of AF and CF as the least integer.
The area of the triangle ABP is 24 cm2 and the ratio of the length of AP and PE is 8 : 1.
(1) Find the area of the triangle ACP.
(2) Find the ratio of the length of AF and CF as the least integer.
Answer
(1) 8 cm2
(2) 6 : 1
(2) 6 : 1
