The figure below is a graphic of six triangles with equal area created by drawing a line in the interior of the triangle ABC.
BC = 24 cm.
Find the length of DF.
BC = 24 cm.
Find the length of DF.
Answer
Therefore, DC =24 cm × 5/(1+5) = 20 cm.
The ratio of the length of the base of △ADE and △EFC is equal to the ratio of the area of two triangles which is 1 : 3.
Therefore, DF = 20cm × 1/(1+3) = 5 cm.
5 cm
Solution
The ratio of the length of the base of △ABD and △ADC is equal to the ratio of the are of two triangles which is 1 : 5.Therefore, DC =24 cm × 5/(1+5) = 20 cm.
The ratio of the length of the base of △ADE and △EFC is equal to the ratio of the area of two triangles which is 1 : 3.
Therefore, DF = 20cm × 1/(1+3) = 5 cm.
