There is a moving sidewalk which moves by a fixed speed between a park and a station.
When Taro walked 80 steps, they passed each other.
Jiro arrived at the station 60 seconds later after Taro's arrival.
Time when Taro took from the station to the park is 60 seconds × 2/(5-2) = 40 seconds.
Because the speed ratio of the speed Taro walks and the moving sidewalk is (5- 2) : 2 = 3 : 2, the speed of the moving sidewalk is 126 × 2/3 = 84 m/m.
Taro went to the park by walking on this moving sidewalk from the station.
Jiro went to the station from the park standing on the moving sidewalk.
They have begun to move at the same time.
When Taro walked 80 steps, they passed each other.
When Taro walked 32 steps after passing, he arrived at the park.
Jiro arrived at the station 60 seconds later after Taro's arrival.
The stride of Taro's one step is 75cm.
Find the speed per minute Taro walks and the speed per minute of the moving sidewalk.
Answer
Taro : 126 m/m
Moving sidewalk : 84 m/m
Solution
Speed of Jiro is speed of the moving sidewalk.
Answer
Taro : 126 m/m
Moving sidewalk : 84 m/m
Solution
Speed of Jiro is speed of the moving sidewalk.
The speed ratio of the sum of speed Taro walks and speed of the moving sidewalk and the speed of Jiro or the speed of the moving sidewalk is 80 : 32 = 5 : 2.
Thus the time ratio moving between the station and the park is to be inverse ratio as 2 : 5.
Time when Taro took from the station to the park is 60 seconds × 2/(5-2) = 40 seconds.
Therefore the speed Taro walks is 75 × (80+32)/40 × 60 = 12600 cm/m =126 m/m.
Because the speed ratio of the speed Taro walks and the moving sidewalk is (5- 2) : 2 = 3 : 2, the speed of the moving sidewalk is 126 × 2/3 = 84 m/m.
