The least common multiple of the two integers X and Y (X< Y) is 96 and 1/X + 1/Y = 19/96.
Find X and Y.
Answer
X = 6, Y = 32
Solution
Divisors of 96 are 1, 96, 2, 48, 3, 32, 4, 24, 6, 16, 8, 12.
When it is set to be as 1/X = A/96 and 1/Y = B/96, A + B = 19 (A < B).
In the multiples of 96, it is found that 3 + 16 = 19.
As 3/96 = 1/32 and 16/96 = 1/6, X = 6 and Y = 32.
Find X and Y.
Answer
X = 6, Y = 32
Solution
Divisors of 96 are 1, 96, 2, 48, 3, 32, 4, 24, 6, 16, 8, 12.
When it is set to be as 1/X = A/96 and 1/Y = B/96, A + B = 19 (A < B).
In the multiples of 96, it is found that 3 + 16 = 19.
As 3/96 = 1/32 and 16/96 = 1/6, X = 6 and Y = 32.
