The sequence of characters of "rikkyoniiza" is repeatedly arranged as rikkyoniizarikkyonizari --------.
Answer the following questions.
(1) Answer the 50th character.
(2) When counting only i, which number from the 1st character is the 2008th i ?
Answer
(1) o
(2) 7361th
Solution
(1)
50 / 11 = 4 remainder 6 → 6th character = o
(2)
i is 3 pieces in one cycle of "rikkyoniiza".
2008 / 3 = 669 cycles and remainder is 1
Remainder 1 means that first i is counted as 2nd character in one cycle.
There are 11 characters in one cycle.
Thus, 669 × 11 + 2 = 7361th
