What cm2 is the shadow area of the figure below?
Solution
(Shadow area) = (Triangle DBC) - (Triangle HBE) - (Triangle DGF).
△ AHD and△ HBE are homothetic and the homothetic ratio is 12 : 6 = 2 : 1.
Since the base of △ HBE = 6 cm and the height = 6 × 1/(1 + 2) = 2 cm, the area is 6 × 2/2 = 6 cm2.
△ ABG and△ DGF are homothetic and the homothetic ratio is 6 : 3 = 2 : 1.
Since the base of △DGF = 3 cm and the height= 12 × 1/(1 + 2) = 4 cm, the area is 3 × 4 / 2 = 6 cm2.
Therefore the shadow area = 12 × 6 / 2 - 6 - 6 = 36 - 12 = 24 cm2.