Mother's age is 5 times of the daughter's age now.
Four years later, mother's age becomes less 4 years less than 4 times of the daughter's age.
Find the the daughter's age now.
In addition, how many years later from now does the mother's age become 4 years less than 3 times of the daughter's age?
Answer
8 years old,
10 years later
Solution
When the current age of the daughter is set to X years old, the age of the mother is X × 5.
Their ages 4 years later are expressed as X × 5 + 4 = (X + 4) × 4 - 4.
When this formula is calculated, X = 8.
Mother is 8 × 5 = 40 years old now.
According to the formula of 40 + Y = (8 + Y) × 3 - 4, Y = 10 years later.
Four years later, mother's age becomes less 4 years less than 4 times of the daughter's age.
Find the the daughter's age now.
In addition, how many years later from now does the mother's age become 4 years less than 3 times of the daughter's age?
Answer
8 years old,
10 years later
Solution
When the current age of the daughter is set to X years old, the age of the mother is X × 5.
Their ages 4 years later are expressed as X × 5 + 4 = (X + 4) × 4 - 4.
When this formula is calculated, X = 8.
Mother is 8 × 5 = 40 years old now.
According to the formula of 40 + Y = (8 + Y) × 3 - 4, Y = 10 years later.
